Question

The graph of which quadratic equation has a vertex of (–2, –1)?

Answer 1

A.y = (x – 2)2 – 1
B.y = (x + 1)2 – 2
C.y = (x + 2)2 – 1
D.y = (x – 1)2 – 2

Answer 2

\[ax^2+bx+c\]
\[(\frac{-b}{2a},f(\frac{-b}{2a}))\]

Looking at your options, choice C looks most likely for -b/2a to = -2
Expand:
\[x^2+4x+4-1=x^2+4x+3\]
-b/(2a)=-4/2(1)=-2
\[f(-2)=(-2)^2+4(-2)+3=4-4+3=-1\]
Therefore; option C is the answer.