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Factor the following trinomials.
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6x^2+5x-6
(3x-2)(2x+3)
\[6y^2-13y-8\]
multiply the coefficient x^2 by the constant 6 x - 6 = 36 find the factors of -36 that add to 5....... 9, -4 then \[((6x + 9)(6x + 4))/6 = (3(2x+3)2(3x-2)/6\] simplifing gives (2x+3)(3x-2)
(3y-8)(2y+1)
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same process multiply 6 x -8 -48... find the factors that add to -13... -16, 3 and then \[((6x -16)(6x +3))/6 = (2(3x - 8)3(2x+1)/6\] simplify (3x -8)(2x+1)
thanks!
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