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2x^2 + 2x - 40
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x^2 +x -20=0
Factor out the 2 first
2(x^2+x-20) 2(x+5)(x-4)
2(x + x - 20) How do I go from there?
Find two numbers whose product is -20 and who sum is 1
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-4(5)=-20 and -4+5=1 So write 2(x+5)(x-4)
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