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y = ^3 square root 7x -9 help..i'm stumped :(
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What is it exactly that you want?
do you mean the cube of square root of (7x-9)? y = (7x-8)^(3/2)
I think he means \(y=\sqrt[3]{7x-9}.\)
and as anwar said what do u want to do qith it?
AnwarA has the correct equation. The question is what is the inverse of this equation. f^-1 = ??
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cube both sides: y^3 = 7x - 9 7x = y^3 + 9 x = (y^3 -9) / 7 replace y by x: f^-1 = (x^3 - 9) / 7
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