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Expand the expression. log(base)3 sqrt. 9x Please show work. Thank you.
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\[\log_{3} \sqrt{9x}\]
\[\log_{3}(\sqrt{9}) + \log_{3}(\sqrt{x}) = \log_{3}(3) +\log_{3}(\sqrt{x}) = 1+\log_{3}(\sqrt{x})\]
Thank you soo much^_^ Now i'm understanding this a little!
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