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x^(2)10^x-2x(10^x)=3(10^x) solve equation..
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10^x(x^2 -2x -3) =0 x=1,-3
can you walk me through it please
that was wrong
x^(2)10^x-2x(10^x)=3(10^x)
Factor out 10^x then solve like any other quadratic equation
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so 10^x(x^2-2x)=3(10^x)?
Bring LHS and RHS to same side and solve quadratin x^2 -2x -3
bring what?
all terms to one side
so 10^x(x^2-2x-3)=0
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?
Yep now you have it factorize quadratic and 10^x gives no roots as it is always greater than zero
so final answer is -1,3
1,-3
no -1,3 ...why u get 1,-3?
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YEah it was a test
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