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The sum of five consecutive even integers is 0
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-2,-1,0,1,2
ops evn only
n n+1 n+2 n+3 n+4 there are 5 consecutive integers the sum means we have n+(n+1)+(n+2)+(n+3)+(n+4) we want this sum to be 0 so we have n+(n+1)+(n+2)+(n+3)+(n+4)=0 Collect like terms 5n+10=0 5n=-10 n=-2 if n=-2, then n+1=-1 n+2=0 n+3=1 n+4=2
oops i missed that part too lol
-4,-2,0,2,4
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