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2^(4/log_2(x)=1/256 solve for x
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\[2^{4/l \log_{2}x}=1/256\]
1/256 = 2^(-8) equating powers 2^(-8) = 2^2/log(x) Log(x) = 2^2/2^(-8) log(x) = 2^(10) then x = (2)^(2^10)
which is?
2^1024
it says to answer to 4 decimal places...
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