Question

Derive this results \[\mathcal{L}\{1\}=1/p\]

Answer 1

\[\mathcal{L}\{1\}=\int_0^∞(1)e^{-pt}dt\]\[={1 \over -p}e^{-pt}|_0^∞\]\[=0-{1 \over -p}\]\[=1/p\]