Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640.?

The chart below summarizes the 2008 population for five U.S. States.

U. S. State

2008 Population
Alaska

686,293
California

36,756,666
Hawaii

1,288,198
Idaho

1,523,816
Indiana

6,376,792

What is the probability that a randomly selected U.S. resident did not live in Alaska? Show step by step work. Round solution to the nearest thousandth

I got The probablility, P, that the person lives in alaska=Population of alaska divided by the U.S Population
P= 686,

Question

Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640.?

The chart below summarizes the 2008 population for five U.S. States.
 

U. S. State

 2008 Population
 Alaska

 686,293
 California

 36,756,666
 Hawaii

 1,288,198
 Idaho

 1,523,816
 Indiana

 6,376,792
 
What is the probability that a randomly selected U.S. resident did not live in Alaska? Show step by step work. Round solution to the nearest thousandth

I got The probablility, P, that the person lives in alaska=Population of alaska divided by the U.S Population 
P= 686,

andijo76 · Answer

oops P=686,293/303.824,640 = this as far as I got

paxpolaris · Answer

If that is the probability of the person being from Alaska.... The probability that the person is not from Alaska is  $${303,824,640-686,293 \over 303,824,640}\ or\  1-{686,293/303,824,640}$$