Question

let f(x)=(x-2)/(3x+3) find an equation for the tangent line to the graph of f at x=10

Answer 1

f(10)=8/33

f'(x)=1/(x+1)^2
f'(10)=1/121

y-y0=m(x-x0)

thus equation is:
y-8/33=(1/121)(x-10)