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write the equation 2x^2+2y^2=8x-16y-32
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state whether the graph is a parabola, ellipse,hyperbola or circle
It is a circle.
2x^2 - 8x + 2y^2 +16y = -32 x^2 - 4x + y^2 + 8y = -16 x^2 - 4x +y^2 + 8y + 16 = 0 not a lot else to do...
2 (x-2)^2+2 (y+4)^2-8 = 0
Divide out a 2 --> (x-2)^2 +(y+4)^2 = 4 circle with radius 2 and center (2,-4)
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