Question

find the area bounded by the graph y = 4x^2 -1, the x axis and the ordinates x = -1/2 and x=1

Answer 1

\[A = \int\limits_{1/2}^{1}(4x^{2} -1) dx\]

Answer 2

smartcow, i thought the ordinates were from -1/2
where did you get the 1/2 from?

Answer 3

well when i graphed it, the parabola from -1/2 to 1/2 is below the x-axis ?

Answer 4

so ....?

Answer 5

is it bounded by the x-axis above or below ?