**Calc2 Help Needed** Find the area of the surface generated by revolving the curve x = (e^y + e^-y) / 2 from x = 0 to x = ln(2).

Question

anonymous · Answer

This is around the y-axis..

anonymous · Answer

Yeah it is surface area not volume, though.

turingtest · Answer

oh dang...

anonymous · Answer

hmm.. Still confused.. do i need u-substitution?

anonymous · Answer

Hi ... 

Ummm its nice equ :D 

i have somethings to say .. i dont know whither its true or not .. but i like to share it 

x = cosh y 

while x cannot be zero ... but we can say when y = 0 , x = 1 

you need to find area .. so we need to enclose the draw 

|dw:1328090291826:dw|

so what is range ? cause x cannot be zero ???? 

in other word what is the area that we want to cal. ^_^!