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**Calc2 Help Needed** Find the area of the surface generated by revolving the curve x = (e^y + e^-y) / 2 from x = 0 to x = ln(2).
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This is around the y-axis..
Yeah it is surface area not volume, though.
oh dang...
hmm.. Still confused.. do i need u-substitution?
Hi ... Ummm its nice equ :D i have somethings to say .. i dont know whither its true or not .. but i like to share it x = cosh y while x cannot be zero ... but we can say when y = 0 , x = 1 you need to find area .. so we need to enclose the draw |dw:1328090291826:dw| so what is range ? cause x cannot be zero ???? in other word what is the area that we want to cal. ^_^!
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