Question

when the equation a to the second power+10a+12=0 is solved using the quadratic formula one of the root is

Answer 1

a^2+10a+12

x=[-b+/-sq rt (b^2-4ac)]2a

a=1
b=10
c=12

x=[-10+/-sq rt (10^2-4(1)(12)]/2(1)

x=[-10+/-sq rt (100-48)]/2

x=[-10+/-sq rt (52)]/2

x=[-10+/-sq rt (4)(13)]/2

x=[-10+/-2 (sq rt 13)]/2

x=-5+/-sq rt 13

x=-5+sq rt 13 and -5-sq rt 13