Question

-3x^2+(1/2)x=2(1/2)

Answer 1

isn't 2(1/2) == 1??

Answer 2

no its 2.5 sorry

Answer 3

\[-3x^2+(1/2)x=1\]
\[-3x^2+(1/2)x-1=0\]

Answer 4

ok put 2.5 in place of my 1.
Use the quadratic formula to solve it

Answer 5

\[-3x^2+\frac12x=2\frac12\]\[\implies 3x^2-\frac 12x+\frac52=0\]\[\implies 6x^2-1x+5=0\]

Answer 6

i have to have a imaginary number

Answer 7

\[\huge x= {-b \pm \sqrt{b^2-4ac} \over 2a}\]

Answer 8

\[x={1 \pm \sqrt{1-4\cdot30} \over 2\cdot6}={1 \pm \sqrt{119}i \over 12}\]