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how do i solve u=3x+1/2x+5 for x... show work pls
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\[u=\frac{3x+1}{2x+5}\] Multiply (2x+5) on both sides.
got that far
\[(2x+5)u=3x+1\] Distribute! \[2x u +5 u =3x +1\]
put terms with u on one side and terms without u on the other side
alright, then haha?
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\[2 x u-3 x= 1- 5u\] sorry i wrote that backwards terms with x on one side and terms without x on the other
now factor \[x(2 u -3) =1- 5u\]
\[x=\frac{1 - 5u}{2u -3}\]
got it. thank you :D
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