Question

Let y=(6 x+1/x)^(-2). Then

(dy)/(dx) = A(6 x+1/x)^B (6-1/(x^C))^D, where

Answer 1

how can I find A,B,C, & D

Answer 2

chain rule in action

Answer 3

\[y=(6x+\frac{1}{x})^{-2}\]
\[y'=-2\times (6x+\frac{1}{x})^{-3}\times \frac{d}{dx}[(6x+\frac{1}{x})\]
\[y'=-2(x6+\frac{1}{x})^{-3}(6-\frac{1}{x^2})\]