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(7u+6v)(7u-6v) how can u do this?
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Difference of squares.
\[(a+b)(a-b)=a^2-b^2\]
You can FOIL it
\[a=7u , b=6v\]
7u*7u=49u^2 7u*6v and 7u*-6v cancel out 6v*-6v=-36v^2 49u^2-36v^2
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so 49u^2-36v^2 will be the answer cuz i get something different? =(
yes it is
thanks very much =)
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