Mathematics
7 Online
OpenStudy (anonymous):
who know what is multiplying intergers is???
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OpenStudy (anonymous):
multiplying whole numbers such 1,2 ,3 ,4,5,...
OpenStudy (anonymous):
multiplication is multiplication
integer is a whole number
not decimal
OpenStudy (anonymous):
irrational or nething
OpenStudy (anonymous):
nor fraction
OpenStudy (anonymous):
cuz i have a qustion 8x-1x7x-2x1
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OpenStudy (anonymous):
cuz i supper bad at maths
OpenStudy (anonymous):
umm u gotta differentiate btwn what i sthe variable x and what i sthe multiplication sign. Use brackets or this sign* for multiplication
OpenStudy (anonymous):
k ty
OpenStudy (anonymous):
can i be more clear
is it
8x- 1x * 7x -2x *1
OpenStudy (anonymous):
does it have parenthesis?
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OpenStudy (anonymous):
:\
OpenStudy (anonymous):
wats that
OpenStudy (anonymous):
( ) these are parenthesis
OpenStudy (anonymous):
bracets [ ]
OpenStudy (anonymous):
it is like this
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OpenStudy (anonymous):
typing x ^ 2
^
|
L________________this is to denote the exponent sign
OpenStudy (anonymous):
unfortunately it was put backwards
lol
OpenStudy (anonymous):
lemme see wht i can do
OpenStudy (anonymous):
ok ty
OpenStudy (anonymous):
8x-4x-1x-1x6
it is like this right?
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OpenStudy (anonymous):
no the 2nd 1 is a 7 and there is on negative on the seven
OpenStudy (anonymous):
i dont see that on the paper
OpenStudy (anonymous):
is it the top 1?
the one written in pen?
OpenStudy (anonymous):
8x+7x-1x-1x6
then lets work with what you told me then
OpenStudy (anonymous):
here read this\[8\times-1\times7\times-2\times1\]
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OpenStudy (anonymous):
(-) are negative
OpenStudy (anonymous):
i can do this 8x*-1=8
and then i am stuck
OpenStudy (anonymous):
8x-1x7-2x1
you know what
1 * any number is right? is right?
OpenStudy (anonymous):
thats right
OpenStudy (anonymous):
so do not confuse yourself
simplify those first
8x-1x7-2x1
8x-7x-2x
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OpenStudy (anonymous):
does it look easier
OpenStudy (anonymous):
1* x7 =?
OpenStudy (anonymous):
7
OpenStudy (anonymous):
1 times any number
that number happenes to be (x7)
OpenStudy (anonymous):
you have to include the whole thing
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OpenStudy (anonymous):
1 is the co efficient
OpenStudy (anonymous):
ohhhhhhhh i get it now ty
OpenStudy (anonymous):
coefficient of x
OpenStudy (anonymous):
whenever you see
x
or
-x coefficient of 1 but you have this - (1 ) x so it is -1 coefficient
there is a coefficient of 1
OpenStudy (anonymous):
hf :)