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the difference between seven times one number and three times a second number is 25. The sum of twice the first and five times the second is 95, Find the numbers
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7x-3y=25 2x+5y=95 System of equations, do you know how to solve?
not really
OK
You want to solve for one variable in terms of the other.
7x=3y+25 \[x=\frac{3}{7}y+\frac{25}{7}\]
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You then plug this into the other equation
\[2(\frac{3}{7}y+\frac{25}{7})+5y=95\]
\[\frac{6}{7}y+\frac{50}{7}+5y=95\]
Multiply by 7
\[6y+50+35y=665\]
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\[41y=615, y=15\]
7x-3(15)=95 7x=140 x=20
yur so kind thank you
You're welcome
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