Question

Algebra II problem

Find the domain of (5x-(39)^(1/3))^1/2

Answer 1

\[\sqrt{(5x-\sqrt[3]{39})}\]

Answer 2

\[[5x-39^{\frac{1}{3}}]^{\frac{1}{2}}\]

Answer 3

so 5x -39^1/3 cannot be negative. So 5x-39^1/3 must be greater than or equal to 0

Answer 4

\[5x \ge 39^{\frac{1}{3}}\]

Answer 5

the equations are coming out messed up now