Question

Brothers Jack and Poy do brisk walking from their house to school daily. Jack walks at 9 km/h, and oy walks at 5 km/h. When Jack reaches the school, Poy is 500 m away. How far is the school from the boys' house?

Answer 1

1.125km

Answer 2

how ?

Answer 3

Let the time taken by Jack to reach the school be t. the same time will be taken by Poy to travel the distance which is 500 m away from the school.
s=vt where s-displacement, v-velocity and t-time.
9t=0.5+5t
4t=o.5
t=0.125
s=9t
=9*0.125
=1.125km