Question

In Triangle ABC, where angle ACB is a right angle. AC = 4 com, AB = 2BC. Find AB.

Please help me.. I'm seriously confused D;

Answer 1

*cm

Answer 2

Here:
use the Pythagoras theorem to obtain :
4^2 + BC^2 = (2BC)^2
or, 16 + BC^2 = 4BC^2
or,3BC^2 = 16
or,BC^2 = 16/3
or,BC = 4/root3
Therefore,AB = 2BC = 8/root3

Answer 3

I dont understand the part after: or,BC^2 = 16/3.. Why does it become 4/root3 :/

Answer 4

square root 16 = 4

Answer 5

OH ok thx a lot :D