Question

Medals 4 grabs because I realize that I keep asking the same questions,so sorry...but "Find 3f(a-4)-2h(a) if f(x)=x^2 +3x and h(x)=2x^2-3x+5"

Answer 1

lets take three steps
1) first find
\[3f(a-4)\]
2) then find \[2h(x)\]
3) then subtract

Answer 2

\[f(x)=x^2+3x\]
\[2f(a-4)=2\left( (a-4)^2+3(a-4)\right)\]
\[=2\left( (a-4)(a-4)+3a-12\right)\]
\[2\left(a^2-8a+16+3a-12\right)\]
\[2\left(a^2-5a+4\right)\]
\[2a^2-10a+8\]

Answer 3

that was the hard part. easy part is
\[2h(a)=2(2a^2-3a+5)\]
\[=4a^2-6a+10\]

Answer 4

Its 3f...

Answer 5

ok no problem

Answer 6

\[3\left(a^2-5a+4\right)\]
\[3a^2-15a+12\]

Answer 7

\[2a^2-15a+12-(4a^2-6a+10)\]