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(3+5sqrt2)(4-sqrt2)
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Have you tried FOIL?
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Yes
So what did you get?
12-3sqrt2+20sqrt4+5sqrt2
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The Inside is 20sqrt2 isn't it?
\[(3+5\sqrt{2})(4-\sqrt{2})=12-3\sqrt{2}+20\sqrt{2}-5\sqrt{2}\sqrt{2})\]
\[5\sqrt{2}\sqrt{2}=5(2)=10\]
Also \[-3\sqrt{2}+20\sqrt{2}=17\sqrt{2}\]
So we have \[12+17\sqrt{2}+10=22+17\sqrt{2}\]
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Do you understand?
Whoops. It's -10 so the result would be 2+17sqrt2
Okay, yes I do thank you
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