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Mathematics 19 Online
OpenStudy (anonymous):

y= 1/x-2 What is the vertical asymptote for the above function? x = _____

OpenStudy (anonymous):

set the denominator = 0 and solve for x

OpenStudy (anonymous):

x=2 is a vertical asymtote

OpenStudy (anonymous):

x=2 asusming\[y = 1\div(x-2)\]

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