Question

Okay since I don't really know how to use this I'll just post the equation in the reply box. Express y in x.

Answer 1

\[\log_{2} xy = 2 + 3 \log_{2} y - \log_{2} y\]

Answer 2

(all the logs have a base of 2)
logxy=2+3logy-logy
logx+logy=log(4)+log(y^3)-logy
logx-log4=log(y^3)-2logy
log(x/4)=log(y^3)-2log(y^2)
log(x/4)=log((y^3)/(y^2))
log(x/4)=log(y)
y=x/4