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OpenStudy (anonymous):
What is the maximum number of relative extrema contained in the graph of this function? f(x)=3x⁵-x³+4x-2
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Directrix (directrix):
0
OpenStudy (anonymous):
To find the maximum number of relative extrema work out the derivative, set to 0 and solve. f(x)=3x⁵-x³+4x-2 f'(x)=15x^4-3x^2+4 15x^4-3x^2+4=0 has no real roots. So the answer is 0.
OpenStudy (anonymous):
no the answer is 2
OpenStudy (cutiecomittee123):
is the answer really 2
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