Area of Rhombus is 28m^2 and one of its diagonal is 4m.its perimeter is. a.)4root53
b.)36m
c.)2root53
d.)none of the above

Question

Area of Rhombus is 28m^2 and one of its diagonal is 4m.its perimeter is.                                                                        a.)4root53
b.)36m
c.)2root53
d.)none of the above

directrix · Answer

a.)4root53

jhonyy9 · Answer

D1 =4 --- diagonal 1 and D2 is diagonal second 
A =28

so A=2(D1*D2/2)
    28=4*D2/2
    28=2D2

D2 =14 

lenght of a side =sqrt(49+4)=sqrt53

so the perimeter of this rhombus will be 4*sqrt53 
- a. is right if there 4root53 sign 4sqrt53 what is 4 squarroot53

jhonyy9 · Answer

hope so much that is understandably sure

jhonyy9 · Answer

good luck 

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