Question

Area of Rhombus is 28m^2 and one of its diagonal is 4m.its perimeter is. a.)4root53
b.)36m
c.)2root53
d.)none of the above

Answer 1

a.)4root53

Answer 2

D1 =4 --- diagonal 1 and D2 is diagonal second
A =28

so A=2(D1*D2/2)
28=4*D2/2
28=2D2

D2 =14

lenght of a side =sqrt(49+4)=sqrt53

so the perimeter of this rhombus will be 4*sqrt53
- a. is right if there 4root53 sign 4sqrt53 what is 4 squarroot53

Answer 3

hope so much that is understandably sure

Answer 4

good luck

bye