Question

please help with co-ordinate geometry/graphs (question attached)

Answer 1

Take the derivative

Answer 2

(4,18)

Answer 3

y' = 3x^2-18x + 24. Set it equal to 0:
3x^2-18x+24=0
Solve for x:
x^2 - 6x + 8 = 0
(x-4)(x-2) = 0

Answer 4

Another maxima-minima problem.

Answer 5

x = 4
y = 4^3 - 9*4^2 + 24*4 +2 = 18

Answer 6

@bah
(x-4)(x-2) = 0
x=2 is a local maximum

Answer 7

woops sorry lol, u're right. I don't even know where i got that 0 from (probably from the graph) haha

Answer 8

just don't want to confuse indiana. I'm sure you know what is going on...