Question

Solve the following equation. log3(x-2)=-1

Answer 1

rewrite in equivelant exponential from as
\[3^{-1}=x-2\] and solve for x

Answer 2

so would i subtract the -2 from 3

Answer 3

it is not 3, it is
\[3^{-1}=\frac{1}{3}\]

Answer 4

\[\frac{1}{3}+2=\frac{7}{3}=x\]