Question

I need help...I don't understand or know what to do or where to start.
F(x)=-2(x^2-4)/3(x^2+4x+4)

Answer 1

2(x-2)(x+2)
----------- = 2(x-2)/(3(x+2))
3(x+2)^2

- hope so much that is understandably sure

Answer 2

good luck

bye

Answer 3

ok ?

Answer 4

so it is just pretty much like an elimination thing

Answer 5

yes right

Answer 6

so do i try to solve the final equation or no

Answer 7

x^2 -4 =(x-2)(x+2) --- us formula a^2 -b^2 =(a-b)(a+b)
x^2 +4x +4 =(x+2)^2

Answer 8

you need to solve it again ?

Answer 9

so on the 1st 1 would it be 0--x cancels and 2 cancels

Answer 10

so sorry i have missed yes there is -2(x-2)/(3(x+2))

Answer 11

im not understanding what you were saying there in your last response

Answer 12

before i have wrote there in numerator 2(x-2/
i now i have said that there is -2

Answer 13

so you need to solve it ?

Answer 14

than you need to suppose that x not can being -2 because than the denominator will be equal zero and than the fraction is undefined

Answer 15

but x=2 is right

Answer 16

like solution of it

Answer 17

yes i do understand now thank you

Answer 18

http://www.wolframalpha.com/input/?i=%28-2%28x%5E2-4%29%29%2F%283%28x%5E2%2B4x%2B4%29%29

Answer 19

yw
my pleasure

good luck

bye