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Find the equation of the tangent line to the curve r= 3 sin2 theta at theta= pi/3
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I have attached the slope of the curve
What difficulty are you having?
ummm i know the slope but like how wld u find the equation?
like what points would you plug into the equation to find out what the y intercept equals?
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like i am not sure how it works with polar equations
Like have you ever worked with polar equations?
are you still there?
use your equation to find r at theta = pi/3 the (x1,y1) of the tangent point is x1= r cos(pi/3), y1= r sin(pi/3) evaluate m= dy/dx at theta = pi/3. use y - y1 = m(x - x1)
ohhhh i get it :D I am so stupid lol
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