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Chemistry 19 Online
OpenStudy (anonymous):

how many moles of mgs2o3 are in 195 g of the compound?

OpenStudy (xishem):

\[195g\ MgS_2O_3 * \frac{1mol\ MgS_2O_3}{136.43g\ MgS_2O_3}=1.43mol\ MgS_2O_3\]

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