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OpenStudy (anonymous):
how many moles of mgs2o3 are in 195 g of the compound?
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OpenStudy (xishem):
\[195g\ MgS_2O_3 * \frac{1mol\ MgS_2O_3}{136.43g\ MgS_2O_3}=1.43mol\ MgS_2O_3\]
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