Find the product:
(x2 + 9x + 7)(3x^2 + 9x + 5)

a.3x^4 + 36x^3 + 17x^2 + 18x + 3
b.3x^4 + 27x^3 + 81x^2 + 53x + 35
c.3x^4 + 36x^3 + 107x^2 + 108x + 35
d.3x^4 + 27x^3 + 107x^2 + 18x + 5

Question

Find the product:
(x2 + 9x + 7)(3x^2 + 9x + 5)

a.3x^4 + 36x^3 + 17x^2 + 18x + 3
b.3x^4 + 27x^3 + 81x^2 + 53x + 35
c.3x^4 + 36x^3 + 107x^2 + 108x + 35
d.3x^4 + 27x^3 + 107x^2 + 18x + 5

xishem · Answer

Multiply each term in the first set of parenthesis with each term in the second set. You'll end up originally with nine terms, before you simplify.

$$(x^2+9x+7)(3x^2+9x+5)$$$$3x^4+9x^3+5x^2+27x^3+81x^2+45x+21x^2+63x+35$$Now combine terms...$$3x^4+36x^3+107x^2+108x+35$$

anonymous · Answer

thank you so much luis!!!!!(: 
and thank you xishem!