Question

the product of two consecutive odd integers is equal to 27 plus six times the sum of the integers. What is the larger integer?

Answer 1

\[n(n+2)=27+6(n+n+2)\] is more like it

Answer 2

once I factor everything out use quadratic formula?

Answer 3

\[n^2+2n=27+6(2n+2)\]
\[n^2+2n=27+12n+12\]
\[n^2-10n-39=0\]

Answer 4

you can factor this one

Answer 5

\[(n-13)(n+3)=0\] etc

Answer 6

13 or -3