Question

Solve using elimination-by-addition method:
9x -6y = 48
10x + 5y = 30

Answer 1

Oh! I think I solved it! :D

Answer 2

we
\[9x-6y=48\]
and
\[10x+5y=30\]
let's eliminate y from the two, let's multiply the first one by 10 and second equation by 12
we have
\[10(9x-6y)=10*48\]
and
\[12(10x+5y)=12*30\]
so we get
\[90x-60y=480\]
and
\[120x+60y=360\]
let's add the two equations, this will eliminate y
\[90x+120x=480+360\]
now combining like terms
we get
\[210x=840\]
dividing both sides by 210 we get
\[x=4\]
now to find y let's substitute x in original first equation (We can use any equation to determine y)
\[9x-6y=48\]
x=4
\[9*4-6y=48\]
\[36-6y=48\]
subtracting both sides by 6 we get
\[-6y=12\]
dividing both sides by -2 , we get
\[y=-2\]
so
x=4 and y =-2

Answer 3

Good Mandi, I didn't see your post, and continued solving. :$

Answer 4

THANK YOU!