Question

Find an equation for the line that is described. Write the answer in two forms. y=mx+b and Ax+By+C=0
Is perpendicular to x-y+2=0 and passes through (3, 1)

Answer 1

x - y + 2 = 0
x + 2 = y
y = x + 2

slope is 1 because 1 is the coefficient of x in this y = mx + b form of a line's equation

Answer 2

The slope of the perpendicular is -1 which is the negative reciprocal of 1, the slope of the first line.

Answer 3

Perpendicular at (3,1)
y - 1 = (-1) ( x - 3)
y - 1 = -x + 3
y = -x + 4 ---> Equation of perpendicular in y = mx + b form

y + x - 4 = 0
1x + 1y -4 = 0 ----> Equation of perpendicular in Ax + By + C = 0 form.

Answer 4

thank you again

Answer 5

Glad to help.