If I have 741.7kg of cranberries, that have 87% moisture content calculate the amount of water removed. The desired moisture content of cranberry sauce is 82% moisture content
36.083 kilos?
is it rite?
96.421
hw raging squirell?
%13 percent of 741.7
sorry i made a mistake i have to calculate the water loss from the total cranberries which is 775kg
So its %13 or %18?
OMG it's really late I just read the question my original post was correct!!! 741.7
Haha, i'm pretty sure your answer is 741.7 or 142 rounded.
no 74107 is the amount of cranberries i have. I need to know how much water is removed from that 741.7
that's ok I'm really confused!!!!
Ohhh! I see it now! 645.279 is your answer.
That's percent by the way. Dont forget to hit "good answer" if i helped you out!
water = moist content - souce 0.87 - 0.82 = 0.05 water weight = 0.05 times 741.7 = 37.085 kg
you are welcome
which is the answer that I got...my problem is i don't know if it's right!!!
Hermione .. Use your magic stick and ...and see what no.s say... my answer so similar to the first answer .. its the basic..its no so hard question here under clarification
|dw:1328517925571:dw|
Join our real-time social learning platform and learn together with your friends!