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Find the values of the constants m and b, for which y=mx + b is a solution to this equation y'=1/2x + y - 1
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You need to find values of \(m \text{ and }b\) that satisfy the equation \[m=\frac{1}{2}x+mx+b-1 \implies x(\frac{1}{2}+m)+b-1=m\] Now, equate coefficients, you get the system: \[\frac{1}{2}+m=0 \implies m=-\frac{1}{2}\] \[b-1=m \implies b=m+1=\frac{1}{2}.\] So, \(m=-\frac{1}{2}\) and \(b=\frac{1}{2}\).
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