Question

Charges q3 and q5 are now replaced by two charges, q2 and q6, having equal magnitude and sign (-3.4 μC). Charge q2 is located at the origin and charge q6 is located a distance d = d1 + d2 = 7.4 cm from the origin as shown. What is ΔPE, the change in potential energy now if charge q1 is moved from point P to point R? d2=2.1cm d1=5.3cm, q1=1.5microC

Answer 1

I believe this would equal zero because the q1 and q2 are equal on opposite sides and it

Answer 2

It would be nice to have a pic...

Answer 3

okay

Answer 4

[url= http://postimage.org/image/ke883kxnr/ ][img] http://s15.postimage.org/ke883kxnr/Potential_energy_Problem.jpg [/img][/url]

Answer 5

There yeah go turmeister

Answer 6

unleash your wrath

Answer 7

zero

Answer 8

turing

Answer 9

cm there

Answer 10

yeah totally zero
sorry, I was busy helping arvind

Answer 11

no prob dooooood/dudet