Question

what is the perpendicular to -7x/6 that passes through point (-8,13)

Answer 1

the opposite inverse of the slope is the slope of your perpendicular rect, so y=6x/7+q, sobstitute x and y => 13=-48/7+q => q=13+48/7 soooo y=6x/7+ (13+48/7)

Answer 2

In two lines, perpendicular means m1*m2=-1
-(7/6)*(6/7)=-1 then m2=(6/7)
(y-13)/(x+8)=6/7 => y=(6/7)x+139/7

Answer 3

@ ricardovg...how did you get 139?

Answer 4

(y-13)/(x+8)=6/7
(y-13)=(6/7)(x+8)
y - 13= (6/7)x+(6/7)*8
y = (6/7)x+(48/7) + 13
y = (6/7)x + (13*7+48)/7
= (6/7)x + (139)/7 ,here it is 139