Question

https://docs.google.com/viewer?a=v&q=cache:oYt47ka7l70J:www.cpo.com/ipcres/pdfs/unit2/Ch4RevQues.pdf+&hl=en&gl=us&pid=bl&srcid=ADGEESj1HjO67kwrGzPsa5R-7C2Hek9yvJv43kvFbNUxKKokbO7Ezx9EryxmavnTz1-4HE4cd-uku0Xeo1vlupXfMmV_QnMX7qa6WfQ3RtchP_GdpiCiZeTytwmyljDEDgLO9owWRzn7&sig=AHIEtbT-lhIJEy39FntuTTp0qi53RVVYIQ last page, #6 ? #help

Answer 1

arg try to do by your self, I think you can do it ! Just fix the variable F out And use the formula T ( torque ) = F * d.

Answer 2

500 x 5

Answer 3

divided by 35?

Answer 4

I don't know, i will try to do here

Answer 5

jaw

T10= 500N * 10cm = 5000cmN

T10=T7= 5000cmN = F * 7cm

F = 714N

arm
T35= 500N * 35cm = 17500cmN

T5 = T35 = 17500cmN = F * 5cm

F = 3500N o,0

Take your own conclusions :P

Answer 6

this is what i did;

500 x 5 = 2,500 / 35

Answer 7

yep =) sorry, i just want keep this in history, in case of some one else have some problem like that