Question

(sqrtx - 3)/(sqrtx + 3) derivative pls

Answer 1

\[y=\frac{\sqrt{x}-3}{\sqrt{x}+3}\]

Answer 2

\[y'=\frac{(\sqrt{x}+3)\times \frac{1}{2\sqrt{x}}-(\sqrt{x}-3)\times \frac{1}{2\sqrt{x}}}{(\sqrt{x}+3)^2}\]

Answer 3

by the quotient rule, then algebra

Answer 4

probably easiest to clean this up by multiplying top and bottom by
\[2\sqrt{x}\]

Answer 5

i got it thanks

Answer 6

\[y=\frac{\sqrt{x}-3}{\sqrt{x}+3}=\frac{\sqrt{x}+3-6}{\sqrt{x}+3}=1-\frac{6}{\sqrt{x}+3}\]\[y \prime=\frac{-6(1/2\sqrt{x})}{(\sqrt{x}+3)^{2}}\]