Question

The doorsill of a campus building is h = 5 feet above ground level. To allow wheelchair access, the steps in front of the door are to be replaced by a straight ramp with constant slope 1/10, as shown in the figure. How long must the ramp be? [The answer is not 50 feet.]...help please :)

Answer 1

\[\frac{1}{10}=\frac{5}{50}\]
\[x=\sqrt{50^2+5^2}=5\sqrt{101} ft \approx 50.2494 ft\]

Answer 2

thank you so much!!!

Answer 3

you're welcome