Question

In Standing Waves,
The condition for an Antinode is (n+1/2)lamda
When considering a pipe open at both the ends,
Antinode is formed at both the ends,
Then why is L = nLamda/2 ?
Shouldnt it be L = (n+1/2)lamda/2 ?

Answer 1

The condition for an antinode is \[x=(2n+1)\lambda/4\]. Check it
and for node is \[x=(n+1)\lambda/2\]. If you r considering sound waves, nodes will be formed at the ends, and the same equations hold. The equation
\[L=n \lambda/2\] is a consequence of the ends being nodal points(u can see it in 8.03 Vibrations and Waves).