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Given that x and y are positive integers, solve x^y = y^x
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can i do the obvious one...x=1, y=1
You have to find all the solutions.Of course 1 is obvious.
Wouldn't all solutions be on a line of y=x?
wait can x=y, if so then any number would work
4 and 2 is another.
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x=y is one . What about x>y?
the only solution is 4 and 2, at least for numbers up to 1000
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