Question

a small ball is released from rest on a smooth plane inclined at 30 degree to the horizontal.find the distance the particle has travelled down the plane when its speed is 6.3m/s.

i've an idea to solve using this formula:
v^2=u^2+2as
but i refuse where we should use the angle given?
please help me..

Answer 1

You have to resolve the acceleration into a horizontal and vertical components

so a = 9.81 sin(30) = 4.905 m/s²

then , you'll use the equation you mentioned

Answer 2

tq ^_^

Answer 3

You Welcome :)