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Mathematics 11 Online
OpenStudy (anonymous):

Evaluate each expression.

OpenStudy (anonymous):

(-3+5i)(-3-5i)

OpenStudy (ash2326):

\[ (-3+5i)(-3-5i)\] rewriting second expression \[(5i-3)*-(5i+3)\] now multiplying using the relation \[(a+b)(a-b)=a^2-b^2\] \[-(25i^2-9)\] we know \(i^2=-1\) so \[-(-25-9)\] we get \[34\]

OpenStudy (anonymous):

9-15i+15i-25i^2 =9-25(-1) =9+25 =34 i^2=-1

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